1900p-0.5p^2=0

Solution for 1900p-0.5p^2=0 equation:

1900p-0.5p^2=0

a = -0.5; b = 1900; c = 0;
Δ = b2-4ac
Δ = 19002-4·(-0.5)·0
Δ = 3610000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3610000}=1900$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1900)-1900}{2*-0.5}=\frac{-3800}{-1}
=+3800
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1900)+1900}{2*-0.5}=\frac{0}{-1}
=0
$